[ty] implement typing.NewType by adding Type::NewTypeInstance
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@@ -1,7 +1,5 @@
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# NewType
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Currently, ty doesn't support `typing.NewType` in type annotations.
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## Valid forms
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```py
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@@ -12,13 +10,389 @@ X = GenericAlias(type, ())
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A = NewType("A", int)
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# TODO: typeshed for `typing.GenericAlias` uses `type` for the first argument. `NewType` should be special-cased
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# to be compatible with `type`
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# error: [invalid-argument-type] "Argument to function `__new__` is incorrect: Expected `type`, found `NewType`"
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# error: [invalid-argument-type] "Argument to function `__new__` is incorrect: Expected `type`, found `<NewType pseudo-class 'A'>`"
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B = GenericAlias(A, ())
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def _(
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a: A,
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b: B,
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):
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reveal_type(a) # revealed: @Todo(Support for `typing.NewType` instances in type expressions)
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reveal_type(a) # revealed: A
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reveal_type(b) # revealed: @Todo(Support for `typing.GenericAlias` instances in type expressions)
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```
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## Subtyping
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The basic purpose of `NewType` is that it acts like a subtype of its base, but not the exact same
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type (i.e. not an alias).
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```py
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from typing_extensions import NewType
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from ty_extensions import static_assert, is_subtype_of, is_equivalent_to
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Foo = NewType("Foo", int)
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Bar = NewType("Bar", Foo)
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static_assert(is_subtype_of(Foo, int))
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static_assert(not is_equivalent_to(Foo, int))
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static_assert(is_subtype_of(Bar, Foo))
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static_assert(is_subtype_of(Bar, int))
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static_assert(not is_equivalent_to(Bar, Foo))
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Foo(42)
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Foo(Foo(42)) # allowed: `Foo` is a subtype of `int`.
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Foo(Bar(Foo(42))) # allowed: `Bar` is a subtype of `int`.
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Foo(True) # allowed: `bool` is a subtype of `int`.
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Foo("forty-two") # error: [invalid-argument-type] "Argument is incorrect: Expected `int`, found `Literal["forty-two"]`"
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def f(_: int): ...
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def g(_: Foo): ...
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def h(_: Bar): ...
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f(42)
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f(Foo(42))
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f(Bar(Foo(42)))
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g(42) # error: [invalid-argument-type] "Argument to function `g` is incorrect: Expected `Foo`, found `Literal[42]`"
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g(Foo(42))
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g(Bar(Foo(42)))
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h(42) # error: [invalid-argument-type] "Argument to function `h` is incorrect: Expected `Bar`, found `Literal[42]`"
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h(Foo(42)) # error: [invalid-argument-type] "Argument to function `h` is incorrect: Expected `Bar`, found `Foo`"
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h(Bar(Foo(42)))
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```
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## Member and method lookup work
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```py
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from typing_extensions import NewType
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class Foo:
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foo_member: str = "hello"
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def foo_method(self) -> int:
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return 42
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Bar = NewType("Bar", Foo)
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Baz = NewType("Baz", Bar)
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baz = Baz(Bar(Foo()))
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reveal_type(baz.foo_member) # revealed: str
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reveal_type(baz.foo_method()) # revealed: int
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```
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We also infer member access on the `NewType` pseudo-type itself correctly:
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```py
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reveal_type(Bar.__supertype__) # revealed: type | NewType
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reveal_type(Baz.__supertype__) # revealed: type | NewType
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```
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## `NewType` wrapper functions are `Callable`
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```py
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from collections.abc import Callable
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from typing_extensions import NewType
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from ty_extensions import CallableTypeOf
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Foo = NewType("Foo", int)
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def _(obj: CallableTypeOf[Foo]):
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reveal_type(obj) # revealed: (int, /) -> Foo
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def f(_: Callable[[int], Foo]): ...
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f(Foo)
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map(Foo, [1, 2, 3])
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def g(_: Callable[[str], Foo]): ...
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g(Foo) # error: [invalid-argument-type]
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```
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## `NewType` instances are `Callable` if the base type is
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```py
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from typing import NewType, Callable, Any
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from ty_extensions import CallableTypeOf
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N = NewType("N", int)
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i = N(42)
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y: Callable[..., Any] = i # error: [invalid-assignment] "Object of type `N` is not assignable to `(...) -> Any`"
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# error: [invalid-type-form] "Expected the first argument to `ty_extensions.CallableTypeOf` to be a callable object, but got an object of type `N`"
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def f(x: CallableTypeOf[i]):
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reveal_type(x) # revealed: Unknown
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class SomethingCallable:
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def __call__(self, a: str) -> bytes:
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raise NotImplementedError
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N2 = NewType("N2", SomethingCallable)
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j = N2(SomethingCallable())
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z: Callable[[str], bytes] = j # fine
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def g(x: CallableTypeOf[j]):
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reveal_type(x) # revealed: (a: str) -> bytes
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```
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## The name must be a string literal
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```py
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from typing_extensions import NewType
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def _(name: str) -> None:
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_ = NewType(name, int) # error: [invalid-newtype] "The first argument to `NewType` must be a string literal"
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```
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However, the literal doesn't necessarily need to be inline, as long as we infer it:
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```py
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name = "Foo"
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Foo = NewType(name, int)
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reveal_type(Foo) # revealed: <NewType pseudo-class 'Foo'>
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```
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## The second argument must be a class type or another newtype
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Other typing constructs like `Union` are not allowed.
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```py
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from typing_extensions import NewType
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# error: [invalid-newtype] "invalid base for `typing.NewType`"
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Foo = NewType("Foo", int | str)
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```
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We don't emit the "invalid base" diagnostic for `Unknown`, because that typically results from other
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errors that already have a diagnostic, and there's no need to pile on. For example, this mistake
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gives you an "Int literals are not allowed" error, and we'd rather not see an "invalid base" error
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on top of that:
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```py
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# error: [invalid-type-form] "Int literals are not allowed in this context in a type expression"
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Foo = NewType("Foo", 42)
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```
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## A `NewType` definition must be a simple variable assignment
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```py
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from typing import NewType
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N: NewType = NewType("N", int) # error: [invalid-newtype] "A `NewType` definition must be a simple variable assignment"
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```
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## Newtypes can be cyclic in various ways
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Cyclic newtypes are kind of silly, but it's possible for the user to express them, and it's
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important that we don't go into infinite recursive loops and crash with a stack overflow. In fact,
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this is *why* base type evaluation is deferred; otherwise Salsa itself would crash.
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```py
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from typing_extensions import NewType, reveal_type, cast
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# Define a directly cyclic newtype.
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A = NewType("A", "A")
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reveal_type(A) # revealed: <NewType pseudo-class 'A'>
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# Typechecking still works. We can't construct an `A` "honestly", but we can `cast` into one.
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a: A
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a = 42 # error: [invalid-assignment] "Object of type `Literal[42]` is not assignable to `A`"
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a = A(42) # error: [invalid-argument-type] "Argument is incorrect: Expected `A`, found `Literal[42]`"
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a = cast(A, 42)
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reveal_type(a) # revealed: A
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# A newtype cycle might involve more than one step.
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B = NewType("B", "C")
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C = NewType("C", "B")
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reveal_type(B) # revealed: <NewType pseudo-class 'B'>
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reveal_type(C) # revealed: <NewType pseudo-class 'C'>
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b: B = cast(B, 42)
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c: C = C(b)
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reveal_type(b) # revealed: B
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reveal_type(c) # revealed: C
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# Cyclic types behave in surprising ways. These assignments are legal, even though B and C aren't
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# the same type, because each of them is a subtype of the other.
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b = c
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c = b
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# Another newtype could inherit from a cyclic one.
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D = NewType("D", C)
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reveal_type(D) # revealed: <NewType pseudo-class 'D'>
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d: D
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d = D(42) # error: [invalid-argument-type] "Argument is incorrect: Expected `C`, found `Literal[42]`"
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d = D(c)
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d = D(b) # Allowed, the same surprise as above. B and C are subtypes of each other.
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reveal_type(d) # revealed: D
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```
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Normal classes can't inherit from newtypes, but generic classes can be parametrized with them, so we
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also need to detect "ordinary" type cycles that happen to involve a newtype.
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```py
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E = NewType("E", list["E"])
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reveal_type(E) # revealed: <NewType pseudo-class 'E'>
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e: E = E([])
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reveal_type(e) # revealed: E
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reveal_type(E(E(E(E(E([])))))) # revealed: E
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reveal_type(E([E([E([]), E([E([])])]), E([])])) # revealed: E
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E(["foo"]) # error: [invalid-argument-type]
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E(E(E(["foo"]))) # error: [invalid-argument-type]
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```
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## `NewType` wrapping preserves singleton-ness and single-valued-ness
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```py
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from typing_extensions import NewType
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from ty_extensions import is_singleton, is_single_valued, static_assert
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from types import EllipsisType
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A = NewType("A", EllipsisType)
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static_assert(is_singleton(A))
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static_assert(is_single_valued(A))
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reveal_type(type(A(...)) is EllipsisType) # revealed: Literal[True]
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# TODO: This should be `Literal[True]` also.
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reveal_type(A(...) is ...) # revealed: bool
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B = NewType("B", int)
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static_assert(not is_singleton(B))
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static_assert(not is_single_valued(B))
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```
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## `NewType`s of tuples can be iterated/unpacked
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```py
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from typing import NewType
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N = NewType("N", tuple[int, str])
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a, b = N((1, "foo"))
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reveal_type(a) # revealed: int
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reveal_type(b) # revealed: str
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```
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## `isinstance` of a `NewType` instance and its base class is inferred as `Literal[True]`
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```py
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from typing import NewType
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N = NewType("N", int)
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def f(x: N):
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reveal_type(isinstance(x, int)) # revealed: Literal[True]
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```
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However, a `NewType` isn't a real class, so it isn't a valid second argument to `isinstance`:
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```py
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def f(x: N):
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# error: [invalid-argument-type] "Argument to function `isinstance` is incorrect"
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reveal_type(isinstance(x, N)) # revealed: bool
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```
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Because of that, we don't generate any narrowing constraints for it:
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```py
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def f(x: N | str):
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if isinstance(x, N): # error: [invalid-argument-type]
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reveal_type(x) # revealed: N | str
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else:
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reveal_type(x) # revealed: N | str
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```
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## Trying to subclass a `NewType` produces an error matching CPython
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<!-- snapshot-diagnostics -->
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```py
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from typing import NewType
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X = NewType("X", int)
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class Foo(X): ... # error: [invalid-base]
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```
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## Don't narrow `NewType`-wrapped `Enum`s inside of match arms
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`Literal[Foo.X]` is actually disjoint from `N` here:
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```py
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from enum import Enum
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from typing import NewType
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class Foo(Enum):
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X = 0
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Y = 1
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N = NewType("N", Foo)
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def f(x: N):
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match x:
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case Foo.X:
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reveal_type(x) # revealed: N
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case Foo.Y:
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reveal_type(x) # revealed: N
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case _:
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reveal_type(x) # revealed: N
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```
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## We don't support `NewType` on Python 3.9
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We implement `typing.NewType` as a `KnownClass`, but in Python 3.9 it's actually a function, so all
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we get is the `Any` annotations from typeshed. However, `typing_extensions.NewType` is always a
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class. This could be improved in the future, but Python 3.9 is now end-of-life, so it's not
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high-priority.
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```toml
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[environment]
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python-version = "3.9"
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```
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```py
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from typing import NewType
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Foo = NewType("Foo", int)
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reveal_type(Foo) # revealed: Any
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reveal_type(Foo(42)) # revealed: Any
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from typing_extensions import NewType
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Bar = NewType("Bar", int)
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reveal_type(Bar) # revealed: <NewType pseudo-class 'Bar'>
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reveal_type(Bar(42)) # revealed: Bar
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```
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## The base of a `NewType` can't be a protocol class or a `TypedDict`
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<!-- snapshot-diagnostics -->
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```py
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from typing import NewType, Protocol, TypedDict
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class Id(Protocol):
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code: int
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UserId = NewType("UserId", Id) # error: [invalid-newtype]
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class Foo(TypedDict):
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a: int
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Bar = NewType("Bar", Foo) # error: [invalid-newtype]
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```
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## TODO: A `NewType` cannot be generic
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```py
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from typing import Any, NewType, TypeVar
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# All of these are allowed.
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A = NewType("A", list)
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B = NewType("B", list[int])
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B = NewType("B", list[Any])
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# But a free typevar is not allowed.
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T = TypeVar("T")
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C = NewType("C", list[T]) # TODO: should be "error: [invalid-newtype]"
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```
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