[syntax-errors] Parenthesized keyword argument names after Python 3.8 (#16482)
Summary
--
Unlike the other syntax errors detected so far, parenthesized keyword
arguments are only allowed *before* 3.8. It sounds like they were only
accidentally allowed before that [^1].
As an aside, you get a pretty confusing error from Python for this, so
it's nice that we can catch it:
```pycon
>>> def f(**kwargs): ...
... f((a)=1)
...
File "<python-input-0>", line 2
f((a)=1)
^^^
SyntaxError: expression cannot contain assignment, perhaps you meant "=="?
>>>
```
Test Plan
--
Inline tests.
[^1]: https://github.com/python/cpython/issues/78822
This commit is contained in:
@@ -702,9 +702,31 @@ impl<'src> Parser<'src> {
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}
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}
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let arg_range = parser.node_range(start);
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if parser.eat(TokenKind::Equal) {
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seen_keyword_argument = true;
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let arg = if let Expr::Name(ident_expr) = parsed_expr.expr {
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let arg = if let ParsedExpr {
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expr: Expr::Name(ident_expr),
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is_parenthesized,
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} = parsed_expr
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{
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// test_ok parenthesized_kwarg_py37
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// # parse_options: {"target-version": "3.7"}
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// f((a)=1)
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// test_err parenthesized_kwarg_py38
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// # parse_options: {"target-version": "3.8"}
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// f((a)=1)
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// f((a) = 1)
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// f( ( a ) = 1)
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if is_parenthesized {
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parser.add_unsupported_syntax_error(
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UnsupportedSyntaxErrorKind::ParenthesizedKeywordArgumentName,
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arg_range,
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);
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}
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ast::Identifier {
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id: ident_expr.id,
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range: ident_expr.range,
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