Test explicit shadowing involving defs (#15174)
Co-authored-by: Carl Meyer <carl@astral.sh>
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@@ -25,3 +25,29 @@ def f(): ...
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f: int = 1
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```
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## Explicit shadowing involving `def` statements
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Since a `def` statement is a declaration, one `def` can shadow another `def`, or shadow a previous
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non-`def` declaration, without error.
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```py
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f = 1
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reveal_type(f) # revealed: Literal[1]
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def f(): ...
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reveal_type(f) # revealed: Literal[f]
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def f(x: int) -> int:
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raise NotImplementedError
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reveal_type(f) # revealed: Literal[f]
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f: int = 1
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reveal_type(f) # revealed: Literal[1]
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def f(): ...
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reveal_type(f) # revealed: Literal[f]
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```
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